3.2312 \(\int \frac{\sqrt{1-2 x} (2+3 x)}{(3+5 x)^{3/2}} \, dx\)

Optimal. Leaf size=72 \[ -\frac{2 (1-2 x)^{3/2}}{55 \sqrt{5 x+3}}+\frac{29}{275} \sqrt{5 x+3} \sqrt{1-2 x}+\frac{29 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{25 \sqrt{10}} \]

[Out]

(-2*(1 - 2*x)^(3/2))/(55*Sqrt[3 + 5*x]) + (29*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/275 + (29*ArcSin[Sqrt[2/11]*Sqrt[3
+ 5*x]])/(25*Sqrt[10])

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Rubi [A]  time = 0.0157993, antiderivative size = 72, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {78, 50, 54, 216} \[ -\frac{2 (1-2 x)^{3/2}}{55 \sqrt{5 x+3}}+\frac{29}{275} \sqrt{5 x+3} \sqrt{1-2 x}+\frac{29 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{25 \sqrt{10}} \]

Antiderivative was successfully verified.

[In]

Int[(Sqrt[1 - 2*x]*(2 + 3*x))/(3 + 5*x)^(3/2),x]

[Out]

(-2*(1 - 2*x)^(3/2))/(55*Sqrt[3 + 5*x]) + (29*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/275 + (29*ArcSin[Sqrt[2/11]*Sqrt[3
+ 5*x]])/(25*Sqrt[10])

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin{align*} \int \frac{\sqrt{1-2 x} (2+3 x)}{(3+5 x)^{3/2}} \, dx &=-\frac{2 (1-2 x)^{3/2}}{55 \sqrt{3+5 x}}+\frac{29}{55} \int \frac{\sqrt{1-2 x}}{\sqrt{3+5 x}} \, dx\\ &=-\frac{2 (1-2 x)^{3/2}}{55 \sqrt{3+5 x}}+\frac{29}{275} \sqrt{1-2 x} \sqrt{3+5 x}+\frac{29}{50} \int \frac{1}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx\\ &=-\frac{2 (1-2 x)^{3/2}}{55 \sqrt{3+5 x}}+\frac{29}{275} \sqrt{1-2 x} \sqrt{3+5 x}+\frac{29 \operatorname{Subst}\left (\int \frac{1}{\sqrt{11-2 x^2}} \, dx,x,\sqrt{3+5 x}\right )}{25 \sqrt{5}}\\ &=-\frac{2 (1-2 x)^{3/2}}{55 \sqrt{3+5 x}}+\frac{29}{275} \sqrt{1-2 x} \sqrt{3+5 x}+\frac{29 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{3+5 x}\right )}{25 \sqrt{10}}\\ \end{align*}

Mathematica [A]  time = 0.0272735, size = 71, normalized size = 0.99 \[ \frac{10 \left (-30 x^2+x+7\right )-29 \sqrt{10-20 x} \sqrt{5 x+3} \sin ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{250 \sqrt{1-2 x} \sqrt{5 x+3}} \]

Antiderivative was successfully verified.

[In]

Integrate[(Sqrt[1 - 2*x]*(2 + 3*x))/(3 + 5*x)^(3/2),x]

[Out]

(10*(7 + x - 30*x^2) - 29*Sqrt[10 - 20*x]*Sqrt[3 + 5*x]*ArcSin[Sqrt[5/11]*Sqrt[1 - 2*x]])/(250*Sqrt[1 - 2*x]*S
qrt[3 + 5*x])

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Maple [A]  time = 0.009, size = 82, normalized size = 1.1 \begin{align*}{\frac{1}{500} \left ( 145\,\sqrt{10}\arcsin \left ({\frac{20\,x}{11}}+1/11 \right ) x+87\,\sqrt{10}\arcsin \left ({\frac{20\,x}{11}}+1/11 \right ) +300\,x\sqrt{-10\,{x}^{2}-x+3}+140\,\sqrt{-10\,{x}^{2}-x+3} \right ) \sqrt{1-2\,x}{\frac{1}{\sqrt{-10\,{x}^{2}-x+3}}}{\frac{1}{\sqrt{3+5\,x}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2+3*x)*(1-2*x)^(1/2)/(3+5*x)^(3/2),x)

[Out]

1/500*(145*10^(1/2)*arcsin(20/11*x+1/11)*x+87*10^(1/2)*arcsin(20/11*x+1/11)+300*x*(-10*x^2-x+3)^(1/2)+140*(-10
*x^2-x+3)^(1/2))*(1-2*x)^(1/2)/(-10*x^2-x+3)^(1/2)/(3+5*x)^(1/2)

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Maxima [A]  time = 2.18689, size = 68, normalized size = 0.94 \begin{align*} \frac{29}{500} \, \sqrt{5} \sqrt{2} \arcsin \left (\frac{20}{11} \, x + \frac{1}{11}\right ) + \frac{3}{25} \, \sqrt{-10 \, x^{2} - x + 3} - \frac{2 \, \sqrt{-10 \, x^{2} - x + 3}}{25 \,{\left (5 \, x + 3\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)*(1-2*x)^(1/2)/(3+5*x)^(3/2),x, algorithm="maxima")

[Out]

29/500*sqrt(5)*sqrt(2)*arcsin(20/11*x + 1/11) + 3/25*sqrt(-10*x^2 - x + 3) - 2/25*sqrt(-10*x^2 - x + 3)/(5*x +
3)

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Fricas [A]  time = 1.22202, size = 224, normalized size = 3.11 \begin{align*} -\frac{29 \, \sqrt{10}{\left (5 \, x + 3\right )} \arctan \left (\frac{\sqrt{10}{\left (20 \, x + 1\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{20 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) - 20 \,{\left (15 \, x + 7\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{500 \,{\left (5 \, x + 3\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)*(1-2*x)^(1/2)/(3+5*x)^(3/2),x, algorithm="fricas")

[Out]

-1/500*(29*sqrt(10)*(5*x + 3)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3)) -
20*(15*x + 7)*sqrt(5*x + 3)*sqrt(-2*x + 1))/(5*x + 3)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{1 - 2 x} \left (3 x + 2\right )}{\left (5 x + 3\right )^{\frac{3}{2}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)*(1-2*x)**(1/2)/(3+5*x)**(3/2),x)

[Out]

Integral(sqrt(1 - 2*x)*(3*x + 2)/(5*x + 3)**(3/2), x)

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Giac [A]  time = 1.97671, size = 132, normalized size = 1.83 \begin{align*} \frac{3}{125} \, \sqrt{5} \sqrt{5 \, x + 3} \sqrt{-10 \, x + 5} + \frac{29}{250} \, \sqrt{10} \arcsin \left (\frac{1}{11} \, \sqrt{22} \sqrt{5 \, x + 3}\right ) - \frac{\sqrt{10}{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}{250 \, \sqrt{5 \, x + 3}} + \frac{2 \, \sqrt{10} \sqrt{5 \, x + 3}}{125 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)*(1-2*x)^(1/2)/(3+5*x)^(3/2),x, algorithm="giac")

[Out]

3/125*sqrt(5)*sqrt(5*x + 3)*sqrt(-10*x + 5) + 29/250*sqrt(10)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3)) - 1/250*sqrt
(10)*(sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) + 2/125*sqrt(10)*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5
) - sqrt(22))